40x+80=10(x^2+4x+4)

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Solution for 40x+80=10(x^2+4x+4) equation:


Simplifying
40x + 80 = 10(x2 + 4x + 4)

Reorder the terms:
80 + 40x = 10(x2 + 4x + 4)

Reorder the terms:
80 + 40x = 10(4 + 4x + x2)
80 + 40x = (4 * 10 + 4x * 10 + x2 * 10)
80 + 40x = (40 + 40x + 10x2)

Add '-40x' to each side of the equation.
80 + 40x + -40x = 40 + 40x + -40x + 10x2

Combine like terms: 40x + -40x = 0
80 + 0 = 40 + 40x + -40x + 10x2
80 = 40 + 40x + -40x + 10x2

Combine like terms: 40x + -40x = 0
80 = 40 + 0 + 10x2
80 = 40 + 10x2

Solving
80 = 40 + 10x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-10x2' to each side of the equation.
80 + -10x2 = 40 + 10x2 + -10x2

Combine like terms: 10x2 + -10x2 = 0
80 + -10x2 = 40 + 0
80 + -10x2 = 40

Add '-80' to each side of the equation.
80 + -80 + -10x2 = 40 + -80

Combine like terms: 80 + -80 = 0
0 + -10x2 = 40 + -80
-10x2 = 40 + -80

Combine like terms: 40 + -80 = -40
-10x2 = -40

Divide each side by '-10'.
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}

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